Determine the excess path loss using the deygout method

Reference no: EM131234712

A 1 GHz transmitter sends a signal to a receiver 4 km away. There are three knife-edged absorbing screens intercepting the direct path. The first screen has an excess height of 5 m and is 1 km from the transmitter. The second screen has an excess height of 10 m and is 2 km from the transmitter. The third screen has an excess height of 5 m and is 3 km from the transmitter. Find the excess path loss using the Deygout method.

Reference no: EM131234712

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