Determine the activation energy for the catalyzed reaction

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Reference no: EM132293242

Question 1. In class, we measured the activity of "flipase" as a function of increasing substrate concentration (number of cards). In the experiment, the concentration of enzyme ([E]T) was 2.0 x 10-6 M. The table shows the data after averaging duplicate measures and expressing activity in cards (mM) per second.

[S]

(mM)

vo

(mM/s)

10

2

15

2.5

20

2.8

25

3

30

2.9

Plot these data as a Lineweaver-Burke plot (1/vo vs 1/[S]) and attached your graph. From this graph, determine the following:

a. Vmax

b. KM

c. kcat (expressed in s-1)

d. kcat/KM (expressed in M-1 s-1)

Question 2. Consider performing the same reaction of flipping cards and including playing cards that looked like the actual cards but could not be flipped, i.e., a competitive inhibitor. If the competitive inhibitor was included at 1.00 mM and it has an inhibition constant (KI) of 0.25 mM, how would this affect the Vmax, the KM, and the rate of reaction (vo) at the lowest concentration of cards (10 mM)?

Question 3a. Based upon the value of kcat from question 1, determine the activation energy (ΔGcat) for the catalyzed reaction (assuming T = 25°C). Show your work.

Question 3b. If our enzyme enhanced rates of reaction by 109-fold, what are the first order rate constant (kuncat) and activation energy (ΔGuncat) of the uncatalyzed reaction (at T = 25°C)?

Verified Expert

The paper is about plotting lineweaver burke plot using substrate and enzyme concentrations. By plotting the graph of 1/[s] vs 1/v0 in excel, a linear equation will be obtained from the graph. The obtained linear equation was used to calculate the values of Km and Vmax.The obtained values are further used to calculate other parameters like Kcat and others. The paper also describes about the affect of competitive inhibitors on Vmax, Km and the rate of reaction. The paper also emphasises on the activation energy of the enzyme catalyzed reactions and also their calculation in presence of catalyst and in absence of catalyst.

Reference no: EM132293242

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Reviews

len2293242

4/25/2019 4:17:02 AM

this question is not hard, just a Linweaver-Burk plot of Michaelis-Menten equation, which is a double inverse plot. I will help along as you proceed. I will add more question on Friday for the inhibitory substrate.

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