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For the following electrochemical cell: Pt1 /O2 (g) (1 atm)/H+, Cl- (0.05M)//H +, Cl - (1.00 M)/O2(g) (1 atm)/Pt2
a) Calculate the cell equilibrium potential, Ecell . Be sure to include the liquid/liquid junction potential in your analysis. Assume that the cation transference number, t +, equals 0.83 regardless of electrolyte concentration and that a H+ = a Cl-.
b) Determine which electrode (Pt 1 or Pt 2) is the anode and cathode, respectively. Why?
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