Compute the wavelength of the second source

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Light of wavelength 630 nm passes through a grating and then onto a screen located several meters from the grating. The 1st order bright band is located 0.28mfrom the central maximum. Light from a second source produces a band 0.22m from the central maximum.

Determine the wavelength of the second source. [Hint: If the angular deflection is small, tan theta = sin theta.]

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Reference no: EM13269779

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