Calculate the time constant of the circuit

Reference no: EM13249013

A 13.1 k? resistor and a capacitor are connected in series and then a 12.0 V potential difference is suddenly applied across them. The potential difference across the capacitor rises to 5.58 V in 1.95 µs.

(a) Calculate the time constant of the circuit.

(b) Find the capacitance of the capacitor

Reference no: EM13249013

Questions Cloud

What is the charge on the ion : When an ion accelerates through a potential difference of 2240V, What is the charge on the ion

Define possible structural subunit does the compound contain : A compound's 13C NMR spectrum shows a resonance at 176 and 85 ppm. What possible structural subunit does the compound contain

Find the inductance l and capacitance c of the circuit : The bandwidth of a series resonant circuit is 400 Hz. (a) If the resonant frequency is 4000 Hz, find Q. (b) If R = 10 ohm, what is the value of XL at resonance

How might a person acquire these abilities : Besides cultural differences, what other factors affect HRM in an organization with international operations?

Calculate the time constant of the circuit : A 13.1 k? resistor and a capacitor are connected in series and then a 12.0 V potential difference is suddenly applied across them, Calculate the time constant of the circuit

Compute the impedance of the circuit : A 260(omega) resistor is in series with a 9.50×10?2H inductor and a 0.56 (mu)F capacitor. Compute the impedance of the circuit at a frequency of f1 = 500 Hz

Define what is the molarity of the acetic acid solution : A 10.0 mL sample of vinegar, which is an aqueous solution of acetic acid, CH3COOH, requires 16.5 mL of a .500 M NaOH solution to reach the end point in a titration. what is the molarity of the acetic acid solution? CH3COOH(aq)+NaOH(aq)>NaCH3COO(aq..

Why is national culture important for companies : Why is national culture important for companies going international?

Explain naoh solution are needed to completely neutralize : how many milliliters of a .215 M NaOH solution are needed to completely neutralize 2.50 mL of a .825 M H2SO4 solution

User Account

All Pages