Tangent at a point of an ellipse Assignment Help

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Tangent at a point of an ellipse:

(i) Let equation of ellipse be 2256_Tangent at a point of an ellipse7.png.

    Slope of tangent to ellipse at a point  (x1, y1)    = 1259_Tangent at a point of an ellipse.png

    Therefore the equation of tangent at (x1, y1) is 1001_Tangent at a point of an ellipse1.png 

     2048_Tangent at a point of an ellipse2.png  i.e.  T= 0

(ii) Equation of tangent at point q that is (a cosθ, b sinθ) is obtained by putting 

x1 = a cosθ,  y1 = b sinθ;       1782_Tangent at a point of an ellipse3.png

EQUATION OF THE TANGENT IN THE TERMS OF ITS SLOPE; USING THE CONCEPT OF COMPARISON:

The equations of tangent to ellipse 2256_Tangent at a point of an ellipse7.png having slope m are y = mx ± 403_Tangent at a point of an ellipse4.png for all the finite values of m.

Moreover the line touches ellipse 338_Tangent at a point of an ellipse5.png.

Illustration: From the point P 2 tangents are drawn one each to ellipse150_Tangent at a point of an ellipse6.png, If the tangents are perpendicular to each other, then find the locus of point P.

Solution:               The tangent at (a cosθ, b sinθ) on 2256_Tangent at a point of an ellipse7.png is

                               703_Tangent at a point of an ellipse8.png        ....(i)

                              The tangent at (a cosΦ, b sinΦ) on 2256_Tangent at a point of an ellipse7.png is

                               741_Tangent at a point of an ellipse9.png        ....(ii)

                              (i) and (ii) are perpendicular 1196_Tangent at a point of an ellipse10.png

                              894_Tangent at a point of an ellipse11.png      ....(iii)

                              By eliminating f from (ii) and (iii)

                              Locus is (x2 + y2)2 = b2 (x + y)2 + a2(x - y)2

 

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