Roots lie in an interval Assignment Help

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Roots lie in an interval:

Here normally we will discuss different useful and sufficient conditions we could impose on a quadratic equation ax2 + bx + c = 0 so that roots of the provided equation lies in a subsequent interval. Since a ≠ 0 , we  may take 

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Case I: Both the roots are positive i.e. they lie in (0, ∞), then the sum of the roots as well as the multiplication of the roots have to be positive.

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Case II: Both the roots are negative i.e. they lie in (-, 0), then the addition of the roots have to be negative and the product of the roots have to be positive.

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Case III: One root is negative and other is positive i.e. origin is lying between the roots. Normally f(0)<0 is the required and sufficient condition.

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Case IV: Both the roots are bigger then a real number k.

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                                    D ≥ 0               ... (1)                                     

                                    f(k) > 0            ...(2)                                      

                                    -b/2a > k         ...(3)                                      

                        These are required & sufficient conditions.       

Case V: If both the roots are less than a real number k.

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                                    D ³ 0               ... (1)                                     

                                    f(k) > 0            ...(2)                                      

                                    -b/2a< k          ...(3)                                      

                        These are required & sufficient conditions.       

Case VI: A real number k is defining between the roots i.e. one root is less then k and other is larger than k.

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                                    D > 0               ... (1)                         

                                    f(k) < 0            ... (2)                         

                        These require & sufficient conditions.    

Case VII: exactly are root is relying between k1 and k2

                        1890_Roots lie in an interval6.png                             

                        f(k1) < 0 and f(k2) > 0                        f(k1) > 0 and f(k2) < 0

                        Hence the sufficient condition is f(k1). f(k2) < 0

 

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