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Perpendicular distance of a point from a line:
Let AB a straight line passing through point A (a, b, c) and having direction cosines l, m, n.
AN = projection of line AP on straight line AB
= l(x - a) + m(y - b) + n(z - c)
and 
∴ perpendicular distance of the point P
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Example: Find out the perpendicular distance of point P (0, -1, 3) from straight line passing through A (1, -3, 2) and with direction ratios 1, 2, 2.
Solution : The direction cosines of line is
The perpendicular distance 
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Projection of a Line:
Projection of line joining 2 point P (x1, y1, z1) and Q (x2, y2, z2) on another line the direction cosines of which are l, m, n is
AB = l(x2 - x1) + m(y2 - y1) + n(z2 - z1)
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