Arithmetico-geometric progression Assignment Help

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Arithmetico-geometric progression:

Consider a1, a2, a3......is an Arithmetic progression. and b1, b2, b3..... is a G.P. Then the series a1b1, a2b2, ....... is called to be an arithmetico-geometric progression (A.G.P). Consequently an arithmetico-geometric progression is of the one of the form ab, (a+d)br, (a+2d)br2, (a+3d)br3,.........

Summation of n Terms:

The addition Sn of first  n  terms  of an  A.G. P.  is calculated in  the  given  way :

Sn = ab + (a + d)br + (a + 2d)br2 +.........+(a + (n - 2)d)brn-2 + (a + (n - 1)d)brn-1

Multiply each sides by r, so that

r Sn = abr + (a + d)br2+.........+(a + (n - 3)d)brn-2 + (a + (n - 2)d)brn-1 + (a + (n - 1)d)brn

Subtracting, we obtain

(1 - r)Sn = ab + dbr + dbr2 +.......+dbrn - 2 + dbrn - 1 - (a + (n - 1)d)brn

1431_Arithmetico-geometric progression.png

If -1 < r < 1, the summation of the infinite number of terms of the progression is

1826_Arithmetico-geometric progression1.png

Problem: Calculate the sum of the series 1.2 + 2.22 + 3.23 + ..... + 100.2100.

Solution:             => = 1.2 + 2.22 + 3.23 + .... + 100.2100

                                    2S =1.22 + 2.23 +  .... + 99.2100 + 100.2101

                              =>  -S = 1.2 + 1.22 + 1.23 + .... + 1.2100 - 100.2101

                              1690_Arithmetico-geometric progression2.png= -2101 + 2 + 100.2101  = 99.2101 + 2.

 

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