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A: void displayBits( unsigned value )
{
const int SHIFT = 8 * sizeof( unsigned ) - 1;
const unsigned MASK = 1<< SHIFT;
cout << setw(10 ) << value << " = ";
for ( unsigned i = 1; i <= SHIFT + 1; i++ )
cout << ( value & MASK ? '1' : '0' );
value <<= 1;
if ( i % 8 == 0 ) // output a space after bits cout << ' ';
}
cout << endl;
You may do the same by divide by 2, till the number is greator than 0. However you ought to use stack to print it in reverse order.
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pseudocode for gregorian calendar
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At a shop of marbles, packs of marbles are prepared. Packets are named A, B, C, D, E …….. All packets are kept in a VERTICAL SHELF in random order. Any numbers of packets with thes
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