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A: void displayBits( unsigned value )
{
const int SHIFT = 8 * sizeof( unsigned ) - 1;
const unsigned MASK = 1<< SHIFT;
cout << setw(10 ) << value << " = ";
for ( unsigned i = 1; i <= SHIFT + 1; i++ )
cout << ( value & MASK ? '1' : '0' );
value <<= 1;
if ( i % 8 == 0 ) // output a space after bits cout << ' ';
}
cout << endl;
You may do the same by divide by 2, till the number is greator than 0. However you ought to use stack to print it in reverse order.
source code for padovan string
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A Padovan string P(n) for a natural number n is defined as: P(0) = ‘X’ P(1) = ‘Y’ P(2) = ‘Z’ P(n) = P(n-2) + P(n-3), n>2 where + denotes string concatenation. For a string of t
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# include stdio.h> # include string.h> # include conio.h> void main() { int i=0,count=0; char a[100],b; clrscr();
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