Every point (x,y) on the curve y=log2 3x is transferred to a new point by the following translation (x',y')=(x+m,y+n), where m and n are integers. The set of (x',y') form the curve y=log2(12x-96). What is the value of m+n?

Posted Date: 3/29/2013 3:44:37 AM | Location : United States

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we have x''''=x+m =>m=x''''-x and        y'''' =y+n =>n=y''''-y hence m+n=(x''''+y'''') - (x+y) taking y''''=y=1 we get m+n= x''''-x putting y=1 in y=log2 3x.... we get x=2/3 putting y''''=1 in y''''=log2 (12x''''-96)... we get x''''=49/6 Hence m+n= x''''-x=49/6 - 2/3                           =45/6=15/2 hence m+n= 15/2 (ANS). Posted by Lisa | Posted Date: 3/29/2013 3:44:55 AM

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