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What happens while a derived-class object is developed & destroyed?
A: Space is allocated (on the heap or the stack) for the full object (i.e. adequate space to store the data members inherited from the base class as well as the data members defined in derived class itself)
The constructor of base class is called to initialize the data members which inherited from the base class
Then the derived class's constructor is called to initialize data members added within the derived class
Then the derived-class object is usable
While the object is destroyed (goes out of scope or it is deleted) the derived class's destructor is called on the object first
The base class's destructor is then called on the object lastly the allocated space for the full object is reclaimed
A: 1. By using const protects you against programming errors which inadvertently alter data. 2. By using const allows function to procedure const and non-const actu
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what are the significances of scope resolution operator? Illustrate with example
Polymorphism C++ supports this idea - that different objects do "the right thing "- by function polymorphism and class polymorphism. Poly means many, while morph means form.
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Scope Resolution operator: The scope resolution operator: : is used to access global variable in the inner block. When global and local variable are identical name the scope re
A: It let you to provide an intuitive interface to users of your class, as well as makes it possible for templates to equally work well with classes and built-in/intrinsic types.
In rPeANUt implement the "char getchar()" and "void printstring(char *str)" functions. Using these functions implement the following: void main() { while (1) { ch
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