## Two-or-three-dimensional-motion, Mechanical Engineering

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Net force acting on particle of mass 2 kg is 10N in north direction.At t=o, particle was moving eastwards with 10m/s. Find displacement and velocity of particle after 2 seconds.

Ans)
given force =F=10N

mass M=2kg

velocity u=10m/s

then acceleration a=F/M=10/2=5m/s^2

then displacement=s=ut+1/2at^2

here u=initial velocity

t=time

a=acceleration

then we get the displacement is=30m

2.velocity=u+at

then we get velocity as 20m/s.

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