Triple integral transformed, Mathematics

An elliptical galaxy has gravitational boundaries defiend by 9x2+16y2+144z2=144. A black hole at the center of the galaxy is interacting with dark matter producing a radiation envelope defined by the region inside the cone Z2=27x2+48y2. If the energy density in this envelope is defined by ρ(x,y,z)=Κ |xyz|

Determine the following given the above with K >C

1. Find the volume of space inside the galaxy affected by the interaction using a triple integral transformed into u,v,w space with u=3x, v=4y, w=z

2.the total energy in the envelope.

3. the center of "mass of the energy in the upper and lower cones individually in the (x,y,z) system.

4.the average energy density , ρ, in each cone.

Note: for units you may use the following.  linear dimensions = 10^5 light year

 

 

Posted Date: 2/27/2013 2:55:13 AM | Location : United States







Related Discussions:- Triple integral transformed, Assignment Help, Ask Question on Triple integral transformed, Get Answer, Expert's Help, Triple integral transformed Discussions

Write discussion on Triple integral transformed
Your posts are moderated
Related Questions
Factoring By Grouping It is a method that isn't utilized all that frequently, but while it can be used it can be somewhat useful. Factoring by grouping can be nice, however it

Raul's bedroom is 4 yards long. How many inches long is the bedroom? There are 36 inches within a yard; 4 × 36 = 144 inches. There are 144 inches in 4 yards.

please tell me what is algebra and how i can understand it

Decision Trees And Bayes Theory This makes an application of Bayes' Theorem to resolve typical decision problems. It is examined a lot so it is significant to clearly understan


what is the are of a square that is 2 inches long and 2 inches wide?

what is the difference between North America''s part of the total population and Africa''s part

850ml is to be administered to a person over 8 hours using a drop factor of 20 drops/ml what is the flow rate in gtts/min ?

If A be the area of a right triangle and b one of the sides containing the right angle, prove that the length of the altitude on the hypotenuse is 2  Ab /√ b 4 +4A 2 . An

If OA = OB = 14cm, ∠AOB=90 o , find the area of shaded region.  (Ans:21cm 2 ) Ans:    Area of the shaded region = Area of ? AOB - Area of Semi Circle = 1/2  x 14 x