String manipulation instruction-microprocessor, Assembly Language

Assignment Help:

String Manipulation Instruction

A series of words or data bytes are available in memory at consecutive locations, to be mention to individually or collectively, are known as byte strings or word strings or byte strings. For instance, a string of characters can be located in consecutive memory locations, where each character can be represented by its ASCII equivalent. For mention to a string, two parameters are needed,

(a) Length of the string and

(b) Starting or ending address of the string.

The length of a string is generally stored as count in the CX register. In case of 8085, same structures may be set up by counter and the pointer arrangements.  The counters and pointers can be modified at each iteration until the needed condition for proceeding further is satisfied. Instead, the 8086 supports a set of more powerful instructions for string manipulations.  In case of 8086 string instructions, the decrementing or incrementing of the pointer depends on the direction flag (DF) status. If it is a byte string operation then the index registers are updated by one. Instead, if it is a word string operation then the index registers are updated by two. The counter in both of the cases is decremented by one. It consisits of REP, MOVSW/MOVSB, CMPS, SCAS, LODS, STOS.

 


Related Discussions:- String manipulation instruction-microprocessor

Programming assembly language, Write an 8086 program to find out the number...

Write an 8086 program to find out the number of positive numbers and negative numbers from a given series of signed numbers include flow chart ..

Shl, Assume that the registers are initialized to EAX=12345h,EBX =9528h EC...

Assume that the registers are initialized to EAX=12345h,EBX =9528h ECX=1275h,EDX=3001h sub AH,AH sub DH,DH mov DL,AL mov CL,3 shl DX,CL shl AX,1 add DX,AX

Microprocessor, from pin description it seems that 8086 has 16 address/data...

from pin description it seems that 8086 has 16 address/data lines i.e.AD0_AD15.The physical address is however is larger than 2^16.How this condition can be handled

Interrupt system based on 8259 a-microprocessor, Interrupt System Based on ...

Interrupt System Based on Single 8259 A The 8259A is contained in a 28-pin dual-in-line package that need only a + 5-V supply voltage.  Its organization is shown in given figur

Assignment, Write an assembly program that adds the elements in the odd ind...

Write an assembly program that adds the elements in the odd indices of the following array. Use LOOP. What is the final value in the register?

#title., BINARY TO GRAY CONVERSION

BINARY TO GRAY CONVERSION

Cisc characteristics-microprocessor, CISC Characteristics : The design...

CISC Characteristics : The design of an instruction  set for a computer  might take into consideration  not only machine language constraints,  but  also  the  requirements  i

8088 timing system diagram-Microprocessor, 8088  Timing System Diagram ...

8088  Timing System Diagram The 8088 address/data  bus is divided  in 3 parts (a) the lower 8 address/data  bits, (b) the middle 8 address bits, and (c) the upper 4 status/

External hardware-interrupts-microprocessor, External Hardware-Interrupts ...

External Hardware-Interrupts External hardware-interrupts are generated by controllers of external devices or coprocessors and are connected to the processor pin for Non Mask a

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd