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String Manipulation Instruction
A series of words or data bytes are available in memory at consecutive locations, to be mention to individually or collectively, are known as byte strings or word strings or byte strings. For instance, a string of characters can be located in consecutive memory locations, where each character can be represented by its ASCII equivalent. For mention to a string, two parameters are needed,
(a) Length of the string and
(b) Starting or ending address of the string.
The length of a string is generally stored as count in the CX register. In case of 8085, same structures may be set up by counter and the pointer arrangements. The counters and pointers can be modified at each iteration until the needed condition for proceeding further is satisfied. Instead, the 8086 supports a set of more powerful instructions for string manipulations. In case of 8086 string instructions, the decrementing or incrementing of the pointer depends on the direction flag (DF) status. If it is a byte string operation then the index registers are updated by one. Instead, if it is a word string operation then the index registers are updated by two. The counter in both of the cases is decremented by one. It consisits of REP, MOVSW/MOVSB, CMPS, SCAS, LODS, STOS.
Signal descriptions of 8086 : described below are common for the maximum andminimum mode bothdata lines AD15 -AD0: These are the time multiplexed andmemory I/O address. Addre
Multiply two numbers by using shift and rotate instruction
IInd Generation Microprocessor : The second generation microprocessor by using n MOS technology seemed in the market in 1973. The Intel 8080, of nMOS technology
Can any one assist me with this program. I am not efficient with assembly language and I need assistance badly. I am not asking anyone to do my work I just need help step by step
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#Write a function to calculate the following arithmetic operation and return the result. A = 2 + (3x)3 + y/2n (x, y and n are arguments of the function where x is an integer in the
Assembling a program Microsoft Assembler MASM is one of the simple to use and famous assemblers. All the references and discussions in this section are belonging to the MASM.
You have to write a subroutine (assembly language code using NASM) for the following equation. Dx= ax2+(ax-1)+2*(ax+2)/2
Flag Register : 8086 has a 16-bit flag register which is divided into 2 parts, viz. (a)machine control flagsand (b)condition code or status flags. The condition code flag regi
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