Prove that the intercept of a tangent between two parallel tangents to a circle subtends a right angle at the centre. Since Δ ADF ≅ Δ DFC ∠ADF = ∠CDF ∴ ∠ADC = 2 ∠CDF Similarly we can prove ∠CEB = 2∠CEF Since  || m ∠ADC + ∠CEB = 180o ⇒2∠CDF + 2∠CEF = 180o ⇒ ∠CDF + ∠CEF = 90o In Δ DFE ∠DFE = 90o Posted Date: 4/10/2013 5:27:43 AM | Location : United States

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