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Now it is time to look at solving some more hard inequalities. In this section we will be solving (single) inequalities which involve polynomials of degree at least two. Or, to put it into other terms, the polynomials won't be linear any more. Just as we saw while solving equations the procedure that we have for solving linear inequalities won't work here.
As it's easier to see the procedure as we work an example let's do that. As along with the linear inequalities, we are looking for all of the values of the variable which will make the inequality true. It means that our solution will approximately certainly involve inequalities as well. The procedure that we're going to go through will give the answers in that form.
which of the following are cyclic group G1= G2= G3= G4= G5={6n/n belong to z}
how to do algbra
please help me understand polynomials- i get the small problems but i dont understand larger ones
We will begin with inequalities that only have a single inequality in them. The thing that we've got to keep in mind here is that we're asking to find out all the values of the
please solve this eqution step by step for me hving trouble -58x-26=8x-230.6
Example Find out all the zeroes of P ( x ) = x 4 - 7 x 3 + 17 x 2 -17 x + 6 . Solution We found the list of all possible rational zeroes in the earlier example. Follo
-3y=4x+24
4x^2+8x-16=0
Qs1=-7+P1 (2) Qd1=15-P1+2P2+P3 (3) Qs1=Qd1
One of my homework questions ask to find the slope and y-intercept of a table and I''ve tried quite a few methods and just can''t figure it out. PLEASE HELP!!
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