Modulus of elasticity, Mechanical Engineering

Assignment Help:

Explain Young's Modulus or Modulus of elasticity?

Sol. : It is ratio between tensile stress and tensile strain or compressive stress and compressive strain. It can be denoted by E. It is same as modulus of elasticity

E  =  σ/e [ σt/et  or σc/ec]

S.No.

Material

Young's Modulus(E)

1

Mild steel

2.1 × 105  N/mm2

2

Cast Iron

1.3 × 105  N/mm2

3

Aluminium

0.7 × 105  N/mm2

4

Copper

1.0 × 105  N/mm2

5

Timber

0.1 × 105  N/mm2

The percent error in calculation of Young's modulus is: [(E1  - E2)/E1] × 100

 


Related Discussions:- Modulus of elasticity

Construction of steam turbine , Construction of steam turbine : CONST...

Construction of steam turbine : CONSTRUCTIO N DETAILS: 1 . Casing: It is made out of cast steel. The casing has rotor inside it. 2 .  Rotor: It carries blades o

Combined gas turbine/Rankine cycle, b. Assuming a 20 MW simple cycle gas tu...

b. Assuming a 20 MW simple cycle gas turbine with a firing temperature of 1600K develop an analysis of a combined cycle. Assume that Tmax in the Rankine cycle is 560 C, Pmax = 60

Moment of inertia.., mathematical expression of moment of inertia

mathematical expression of moment of inertia

3 Games in Supply Chain, I have three assignment in Supply Chain Engineerin...

I have three assignment in Supply Chain Engineering. It is a Games assignment in: 1- Beer Game 2000 words. 2- Risk Pooling Game, Object of this game is to rewrite properly correct

What is data unification, What is Data Unification To optimize the UPR ...

What is Data Unification To optimize the UPR data structures, during design we study the semantics of each data type of the supported CAD systems and identify data types that a

Newton''s ring, Explain construction and working process of newton''s ring

Explain construction and working process of newton''s ring

Engfine, how we made parts of engine

how we made parts of engine

Calculate force required for equilibrium, Calculate force required for equi...

Calculate force required for equilibrium: A member ABCD is subjected to the point loads P 1 , P 2 , P 3   an d P 4   as shown in the figure given below

CENTRE OF GRAVITY OF WIRE, WHATIS CG OF A WIRE BENT IN THE FORM OF A QUARTE...

WHATIS CG OF A WIRE BENT IN THE FORM OF A QUARTER ELLIPSE

Angle of twist is zero on the shaft, Angle of twist is zero on the shaft: ...

Angle of twist is zero on the shaft: A shaft 10 m long and 100 mm diameter during its length is fixed at the ends and is subjected to two opposite torques of 8 kN-m and 10 kN-

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd