Kruskals algorithm, Data Structure & Algorithms

Assignment Help:

Krushkal's algorithm uses the concept of forest of trees. At first the forest contains n single node trees (and no edges). At each of the step, we add on one (the cheapest one) edge so that it links two trees together. If it makes a cycle, simply it would mean that it links two nodes that were connected already. So, we reject it.

The steps in Kruskal's Algorithm are as:

1.   The forest is constructed through the graph G - along each node as a separate tree in the forest.

2.   The edges are placed within a priority queue.

3.   Do till we have added n-1 edges to the graph,

  I.   Extract the lowest cost edge from the queue.

 II.   If it makes a cycle, then a link already exists among the concerned nodes. So reject it.

 III.  Otherwise add it to the forest. Adding it to the forest will join two trees together.

The forest of trees is a division of the original set of nodes. At first all the trees have exactly one node in them. As the algorithm progresses, we make a union of two of the trees (sub-sets), until the partition has only one sub-set containing all the nodes eventually.

Let us see the sequence of operations to determine the Minimum Cost Spanning Tree(MST) in a graph via Kruskal's algorithm. Suppose the graph of graph shown in figure  and below figure  illustrates the construction of MST of graph of Figure

1339_Kruskals Algorithm.png

Figure: A Graph

Figure: Construction of Minimum Cost Spanning Tree for the Graph by application of Kruskal's algorithm

The following are several steps in the construction of MST for the graph of Figure via Kruskal's algorithm.

Step 1 :  The lowest cost edge is chosen from the graph that is not in MST (initially MST is empty). The cheapest edge is 3 that is added to the MST (illustrated in bold edges)

Step 2: The next cheap edge which is not in MST is added (edge with cost 4).

Step 3 : The next lowest cost edge that is not in MST is added (edge with cost 6).

 Step 4 : The next lowest cost edge that is not in MST is added (edge with cost 7).

Step 5 : The next lowest cost edge that is not in MST is 8 but form a cycle. Hence, it is discarded. The next lowest cost edge 9 is added. Now the MST has all the vertices of the graph. This results in the MST of the original graph.


Related Discussions:- Kruskals algorithm

Randomized algorithm, need an expert to help me with the assignment

need an expert to help me with the assignment

Binary search trees, A Binary Search Tree is binary tree which is either em...

A Binary Search Tree is binary tree which is either empty or a node having a key value, left child & right child. By analyzing the above definition, we notice that BST comes int

Abstract data type-list, It is a useful tool for indicating the logical pro...

It is a useful tool for indicating the logical properties of data type. It is a collection of values & a set of operations on those values. Methodically, "a TYPE is a set, & elemen

Implement an open hash table, In a chained hash table, each table entry is ...

In a chained hash table, each table entry is a pointer to a collection of elements. It can be any collection that supports insert, remove, and find, but is commonly a linked list.

Evaluation of arithmetic expressions, Stacks are often used in evaluation o...

Stacks are often used in evaluation of arithmetic expressions. An arithmetic expression contains operands & operators. Polish notations are evaluated through stacks. Conversions of

A bst is traversed in which order recursively, A  BST is traversed in the ...

A  BST is traversed in the following order recursively: Right, root, left e output sequence will be in In Descending order

The complexity of multiplying two matrices, The complexity of multiplying t...

The complexity of multiplying two matrices of order m*n and n*p is    mnp

Efficiency of binary search, Each of the comparison in the binary search de...

Each of the comparison in the binary search decrease the number of possible candidates where the key value can be searched by a factor of 2 as the array is divided into two halves

Depth of complete binary tree, What will be depth do , of complete binary t...

What will be depth do , of complete binary tree of n nodes, where nodes are labelled from 1 to n with root as node and last leaf node as node n

Insertion of an element in a linear array, To delete an element in the list...

To delete an element in the list at the end, we can delete it without any difficult. But, assume if we desire to delete the element at the straining or middle of the list, then, we

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd