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Integrals Involving Trig Functions - Integration techniques
In this part we are going to come across at quite a few integrals that are including trig functions and few methods we can use to help us evaluate them. Let us start off along with an integral that we should previously be capable to do.
∫ cos x sin5 x dx = ∫ u5 du by using the substitution u = sin x
= 1/6 sin6 x+c
This integral is extremely easy to do along with a substitution as the existence of the cosine, although, what about the following integral.
Prove that a m + n + a m - n =2a m Ans: a m + n = a 1 + (m + n - 1) d a m-n = a 1 + (m - n -1) d a m = a 1 + (m-1) d Add 1 & 2 a m+n + a m-n =
how to do them?
A class has 175 learners. The given table describes the number of learners studying one or more of the subsequent subjects in this case Subjects
Utilizes the second derivative test to classify the critical points of the function, h ( x ) = 3x 5 - 5x 3 + 3 Solution T
#question application of vector and scalar in our daily life
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find the diameter of circle whose circumference is 26.51
WON 5 GAMES
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