If one won''t explicitly call the destructor of a local then , C/C++ Programming

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if one won't explicitly call the destructor of a local; then how does he handle the above situation?

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3/15/2013 5:27:11 AM if one won''t explicitly call the destructor of a local; then how does he handle the above situation? A: Just wrap the extent of the lifetime of the local in an artificial block {...}: void someCode() { { File f; ...insert code which should execute while f is still open... } f''s destructor will automatically be called here. ...insert code here which should execute after f is closed...}
3/15/2013 5:33:02 AM if one won''t explicitly call the destructor of a local; then how does he handle the above situation? A: Just wrap the extent of the lifetime of the local in an artificial block {...}: void someCode() { { File f; ...insert code which should execute while f is still open... } f''s destructor will automatically be called here. ...insert code here which should execute after f is closed...}

3/15/2013 5:27:11 AM

if one won''t explicitly call the destructor of a local; then how does he handle the above situation?

A: Just wrap the extent of the lifetime of the local in an artificial block {...}:

void someCode()

{

File f;

...insert code which should execute while f is still open...

} f''s destructor will automatically be called here.

...insert code here which should execute after f is closed...}

3/15/2013 5:33:02 AM

if one won''t explicitly call the destructor of a local; then how does he handle the above situation?

A: Just wrap the extent of the lifetime of the local in an artificial block {...}:

void someCode()

{

File f;

...insert code which should execute while f is still open...

} f''s destructor will automatically be called here.

...insert code here which should execute after f is closed...}

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