if one won't explicitly call the destructor of a local; then how does he handle the above situation?

Posted Date: 3/15/2013 5:26:38 AM | Location : United States

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if one won''t explicitly call the destructor of a local; then how does he handle the above situation? A: Just wrap the extent of the lifetime of the local in an artificial block {...}: void someCode() { {   File f; ...insert code which should execute while f is still open... } f''s destructor will automatically be called here. ...insert code here which should execute after f is closed...}   Posted by | Posted Date: 3/15/2013 5:27:11 AM

if one won''t explicitly call the destructor of a local; then how does he handle the above situation? A: Just wrap the extent of the lifetime of the local in an artificial block {...}: void someCode() { {   File f; ...insert code which should execute while f is still open... } f''s destructor will automatically be called here. ...insert code here which should execute after f is closed...}   Posted by | Posted Date: 3/15/2013 5:33:02 AM

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