Identify the flaw in the following argument which supposedly determines that n^{2} is even when n is an even integer. As well name the reasoning:
Assume that n^{2} is even. After that n^{2} = 2k for some integer k. Let n = 2l for some integer l. This depicts that n is even.
Ans: The flaw lies in the following statement "Let n = 2l for some integer l. This depicts that n is even". This is a loaded and biased reasoning. This can be hence proved by method of contradiction.