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How to catch multiple exceptions explain with example?
If multiple blocks match the exception type, the first block in which matches the kinds of the exception catches it. public class HelloThere {
public static void main(String[] args) { int repeat; try { // possible NumberFormatException and ArrayIndexOutOfBoundsException repeat = Integer.parseInt(args[0]); // possible ArithmeticException int n = 2/repeat; // possible StringIndexOutOfBoundsException String s = args[0].substring(5); } catch (NumberFormatException e) { // print an error message System.err.println("Usage: java HelloThere repeat_count" ); System.err.println( "where repeat_count is the number of times to say Hello" ); System.err.println("and given as an integer like 1 or 7" ); return; } catch (ArrayIndexOutOfBoundsException e) { // pick a default value repeat = 1; } catch (IndexOutOfBoundsException e) { // ignore it } catch (Exception e) { // print an error message and exit System.err.println("Unexpected exception"); e.printStackTrace(); return; } for (int i = 0; i < repeat; i++) { System.out.println("Hello"); } }
}It's rare to catch a general Error or Throwable because it's actually hard to clean up after them in the general case.
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Use a FOR loop and give me the largest number divisible by 7 11 13 17 use the number from 1 to 10000 (or even 100000)
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