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Can both client and server use the same protocol port on the same computer at the same time? Explain.
Client and server can't use similar port number on similar computer at identical time. This is because two end points will be similar and similar port cannot be assigned to two processes. When also a process request a port then new empty port is assigned. Particular socket bind on a remote machine can accept more than one connection from another machine.
The following sentences have a (potential) scope ambiguity. Give two translations into predicate logic for each sentence (one formula for each reading), and explain in words what t
Logical Representations: If every human being spoke the same kind of language, there would be several less misunderstanding in the world. The problem with software engineering
Why a function canot have delays? However in Open Vera, delays are allowed in function. A function returns a value and hence can be used as a part of any expression. This doesn
When the user is inputting commands into your shell, it should properly handle delete and backspace. When one of these characters is detected, you will need to remove one character
Prove the equations A + A‾ .B + A.B‾ = A + B using the Boolean algebraic theorems ? Ans. The equation is A + A‾.B + A.B‾ = A + B L.H.S. = A + A‾ .B + A.B‾ = (A + A.B‾) + A‾.B
Implication connective - Modus ponens rule: We notice that this is a trivial example, so it highlights how we use truth tables: as the first line is the only one when both abo
algorithm of data structer
Q. Versions of small computer systems interface? SCSI-1 calls for a cable with 8 data wires plus one for parity. SCSI-2 allows use of multiple cables to support 16- or
Explain essential loop in Process Scheduling . The complex part of scheduling is to balance policy enforcement along with resource optimization so as to pick the best job to run
What do you mean by memory mapped I/O? In Memory mapped I/O, there is no particular input or output instructions. The CPU can manipulate I/O data residing in interface register
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