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The number of calories needed on a daily basis for a moderately active male is found to be k(calories)= 1108 + ( w + h - a ) where w is his weight in pounds, h is his height in inc
how to do factorization by taking out the common factor
2x+5
y = 4 - 3x /1 + 8x for x. Solution This one is very alike to the previous instance. Here is the work for this problem. y + 8xy = 4 - 3x 8xy + 3x = 4 - y X(8 y +3)
8/10 3/8
20
14th term 60, 68, 76, 84, 92, ...
7x-4y=19;17x-2y=-31
how do you work out 2x-y=32 2x+y=60
x+3/4=41/3
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