## Four quadrant chopper or class e chopper , Electrical Engineering

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Four  Quadrant Chopper or Class E chopper

Figure class E chopper circuit

Mode I

When SW1  is ON  with SW4 V0 = Vs and load current  flows  as shown  in figure  when SW1 is OFF  V0 = 0  but current  will continuously be flowing  through  SW\$ and diode  D2. Here both V0 and I0 will be positive hence it is first quadrant operation as shown  in figure.

Mode II

When SW2  is ON  with diode D4 V0= 0 but the  direction of current  will be  negative.  When SW2  is OFF diode D1  and D4  will be conducting  in this period  power flows  from load  to source  because V0 = E+ L di/dt exceeds Vs. Hence  Vo is positive  but current  is negative. This give the  second  quadrant operation as  show in figure.

Mode III

In this  mode the  polarity off must  be reverses so that  third  quadrant operation can be  obtained. Now  when SW2 is ON with SW2 , V0 = -Vs and  current will  be flowing in reverse direction. Both  Vo  and Io  will be  negative. When SW3 is OFF D2 will conduct with  SW2 therefore  both V0 and Io  will be  negative. Hence third  quadrant operation is obtained.

Mode IV

Diode D2  must be  conducting  with SW4 On E  have opposite polarity to that shown in figure  now the  voltage  V0= 0  whenSW4 is ON  and  current  10 will be  positive  when SW4 is OFF V0 will be  negative but current  remains in  same  direction. In this condition power  flows  from load to source and  V0 = -( E+ L di/dt) exceeds Vs.

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