Formula for maximum power transmitted by belt:
Derive formula for maximum power transmitted by belt when centrifugal tension is considered.
Sol: Let T1 = Tension on tight side T2 = Tension on slack side v = Linear velocity of belt
Then the power transmitted can be given by the equation
Power transmitted will be maximum if d(P)/dv = 0
Thus differentiating equation with respect to V and equating to zero for maximum power, we get
Equation (iv) gives velocity of belt at which maximum power is transmitted.
From equation (iv) Tmax = 3Tc ...(v)
Hence when power transmitted is maximum, the centrifugal tension would be around 1/3rd of the maximum tension.
We know that Tmax = T1 + Tc
Hence condition for transmission of maximum power is:
Tc = 1/3 Tmax, and
T1 = 2/3Tmax ...(viii)
NOTE: The net driving tension in the belt = (T1 - T2)