Find the values of k, Mathematics

If the vertices of a triangle are (1, k), (4, -3), (-9, 7) and its area is 15 sq units, find the value(s) of k..                                                                                                                                                      [Ans: -3 ,21/13 ]

Ans:    A(1, k)             B(4, -3)            C(-9, 7)

Area of Δ ABC =1/2 [x1(y2 -y1 )+x2 (y3 -y1 ) + x1 (y1 -y2 )]

= 1/2 [1(-3-7)+4(7-k)+(-9)(k+3)] = 15

-10 + 28 - 4k - 9k - 27 = 30

- 9 - 13k = 30            ⇒        k = -3

| -9 - 13k | = 30

9 + 13k = 30

k = 21/13

k = -3, 21/13



Posted Date: 4/10/2013 2:33:17 AM | Location : United States

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