The hypotenuse of a right triangle is 20m. If the difference between the length of the other sides is 4m. Find the sides.
Ans: APQ
x^{2} + y^{2} = 202 x^{2} + y^{2} = 400 also x - y = 4
⇒ x = 404 + y
(4 + y)^{2} + y^{2} = 400
⇒2y^{2} + 8y - 384 = 0
⇒(y + 16) (y - 12) = 0
⇒ y = 12 y = - 16 (N.P)
∴sides are 12cm & 16cm