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The hypotenuse of a right triangle is 20m. If the difference between the length of the other sides is 4m. Find the sides.
Ans: APQ
x2 + y2 = 202 x2 + y2 = 400 also x - y = 4
⇒ x = 404 + y
(4 + y)2 + y2 = 400
⇒2y2 + 8y - 384 = 0
⇒(y + 16) (y - 12) = 0
⇒ y = 12 y = - 16 (N.P)
∴sides are 12cm & 16cm
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