Example of Log Rules:
Y = ½ gt^{2} where g = 32
Solution:
y = 16 t^{2}
Find y for t = 10 using logs.
log y = log_{10} (16 t^{2})
log_{10}y = log_{10} 16 + log_{10} t^{2}
log_{10}y = log_{10} 16 + (2 log_{10} t)
log_{10}y = 1.204 + 2 log_{10} 10
log_{10}y = 1.204 + 2 x 1
log_{10}y = 3.204
but this means 10^{3.204 }= y
y = 1600