Do friends break encapsulation?, C/C++ Programming

A: No. If they're utilized properly, they increase encapsulation.

You frequently require splitting a class in half while the two halves will have distinct numbers of instances or distinct lifetimes. In these cases, usually the two halves need direct access to each other (the two halves utilized to be in the similar class, thus you haven't enhanced the amount of code that required direct access to data structure; you've simply reshuffled the code in two classes rather than one). The safest method to implement it is to make the two halves friends of each other.

If you employ friends like just defined, you'll keep private things private. People who don't understand this frequently make naive efforts to ignore using friendship in situations such as the above, and frequently they in fact destroy encapsulation. They either employ public data (grotesque!), or they make the data accessible among the halves using public get() and set() member functions. Having a public get() & set() member function for private datum is OK only while the private datum "makes sense" from outside the class (from a user's perspective). In several cases, these get()/set() member functions are approximately as bad as public data: they hide (only) the name of the private datum, however they don't hide the existence of the private datum.

Likewise, if you employ friend functions as a syntactic variant of a class's public access functions, they don't break encapsulation any more than a member function breaks encapsulation. In other terms, a class's friends don't violate the encapsulation barrier: along the class's member functions, they are the encapsulation barrier.

 (Several people think of a friend function as something outside the class. Rather then, try thinking of a friend function as part of the class's public interface. In the class declaration a friend function doesn't violate encapsulation any more than a public member function break encapsulation: both have exactly the similar authority with respect to accessing the class's non-public parts.)

 

Posted Date: 3/20/2013 4:03:41 AM | Location : United States







Related Discussions:- Do friends break encapsulation?, Assignment Help, Ask Question on Do friends break encapsulation?, Get Answer, Expert's Help, Do friends break encapsulation? Discussions

Write discussion on Do friends break encapsulation?
Your posts are moderated
Related Questions
Raj is a newbie to the programming and while learning the programming language he came to know the following rules: · Each program must start with ''{'' and end with ''}''

Create a .cpp program that verifies the strength of a password that a user is entering is strong (complex/secure) enough. In the main area of the program, prompt the user to enter

#include long BixFunction(int x, int y = 5, float z = 5) { return(++x * ++y + (int)++z); } int main() { cout return 0; }

Operators The variables, which are declared and explained, are the operands, which are operated upon by the operators. Operators specify what operations are to be performed on

How can I handle a destructor that fails? Need help please provide example also.

P o i n t e r d e c l a r a t i o n f o r C l a s s : M m; M * p m; / / C la ss M i s d e c l a r e d a s

Implementing files in c++

#include stdio.h> #include conio.h> #include ctype.h> #include string.h>   void main() {           int i=0,j=0,length;           char a[30];           cl

The #define Directive The #define directive explains a macro which is a text string represented by a name. Whenever the pre-processor finds this name in the program, it is repl

It is a feature in C++ to reduce name collisions in the global name space. This namespace keyword assigns a separate name to a library that allows other libraries to use the simila