Discover the maximum safe air pressure:
A cylindrical compressed air drum is equal to 2 m in diameter along plates 12.5 mm thick. The efficiencies of the longitudinal (η_{l}) and circumferential (η_{c}) joints are equal to 85% & 45% respectively. If in the plating the tensile stress is to be limited to 100 MN/m^{2}, discover the maximum safe air pressure.
Solution
The efficiency of the joint effect the stresses induced. For a seamless shell (with no joints), efficiency is equal to 100%. While the efficiency of joint is less than 100%, the stresses are enhanced accordingly.
Therefore, if η is the efficiency of a joint in the longitudinal direction, affecting the hoop stress, then the stress shall be given as,
σ_{ h} = pd/ (4t ×η_{I})
Here, the diameter d = 2 m = 2000 mm.
Thickness, t = 12.5 mm.
Limiting tensile stress = 100 MN/m^{2} = 100 N/mm^{2}.
Letting the circumferential joint which influences the longitudinal stress,
Pd/ (4t × ηl) = 100
p × 2000 / (4 × 12.5 × 0.45) = 100
p = 1.125 N/mm^{2}
Likewise, considering the longitudinal joint which influences the hoop stresses,
pd / (2t × ηc) = 100
p × 2000 / (2 × 12.5 × 0.85) = 100
p = 1.063 N/mm^{2}
Evidently, safe pressure is governed through hoop stress.
Therefore, maximum safe air pressure = 1.063 N/mm^{2}.