Differentiate outline function in chain rules, Mathematics

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Differentiate following.

1924_outside function.png

Solution :It requires the product rule & each derivative in the product rule will need a chain rule application as well.

T ′ ( x ) =1/1+(2x)2 (2) (1-3x2)(1/3) +tan-1(2x)(1/3)(1-3x2)(-2/3)(-6x)

= 2(1 - 3x2 )(1/3)  /(1+(2x)2 - 2(1 - 3x2 )-(2/3)  tan -1 ( 2x )

We know that,

d (tan -1 x ) / dx =  (1/(1+x2)

While doing the chain rule with this we remember that we've got to leave the inside function

alone. That means that where we have the x2  in the derivative of tan -1 x we will have to have (inside function )2 .


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