Determine the value of maximum power:
Determine the value of load resistance, R_{L }for which the source shall transfer the maximum power. Also determine the value of maximum power.
Solution
Primary we apply the Thevenin theorem and draw the Thevenin's equivalent circuit. Eliminate the load resistance RL.
Calculation for V_{TH} :
V_{TH} = Open circuit voltage across load terminals AB, and
= V_{AB}
V_{AB} = V_{TH}
= - 5 + 4 i
=- 5 + 4 ( 10/6)
= 1.66 Volt
Calculation for R_{TH }:
Replace all of the sources by internal resistance. (Internal resistance of ideal voltage source is zero)
R_{TH } = R_{AB}
= 2 // 4 + 6
= (2 × 4 )/(2 + 4) + 6
= 7.33 Ω
Thevenin's Equivalent Circuit
According to maximum power transfer theorem
R_{L} = R_{TH} = 7.33 Ω
i_{L }= 1.66 / (7.33 + 7.33) = 0.1132 Amp
Maximum power P_{max} =( i _{L })^{2} × R_{L}
= 0.09398 Watts
= 93.98 m Watts