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Determine the rate of communication line
The dog could carry 21 gigabytes or 168 gigabits. A speed of 18 km/hour that is equal to 0.005 km/sec. The time to travel the distance x km is x/0.005 = 200x sec, yielding data rate of 168/200x Gbps or 840/x Mbps. For x< 5.6 km, dog has a higher rate than communication line.
Q. Show the Congestion avoidance in TCP? Slow Start (SS) & Additive Increase (AI) (AI=Congestion Avoidance) start with the congestion window (cwnd) = max segment si
A logical circuit that is created by Virtual channel links. It carries data among two endpoints in a network. The one more name for Virtual Channel is Virtual Circuit.
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What is Frequency borrowing In the simplest case, frequencies are taken from adjacent cells by congested cells. The frequencies can also be assigned to cells dynamically.
is DVMRP multicast prtocol supports IPV6?
What is the difference between routable and non- routable protocols? Ans) Routable protocols can work with a router and can be used to build huge networks. Non-Routable protocol
CONNECTION-ORIENTED: Accounting is simpler. Application can learn of network causes immediately. CONNECTIONLESS: It has fewer load. It is easier to cre
INTERNETWORKING - TCP/IP 1. State the following terminologies: a) Node b) Router c) Host d) Subnet e) Network 2. What do you understand by IEEE 802 Local Area network 3.
ONE TO MANY
COMPUTER NETWORKS 1. What do you mean by open system? What is the purpose of OSI model? Explain the layered architecture of OSI model. 2. Define the following terms: a) Ana
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