Determine net work done, Mechanical Engineering

Determine net work done:

5m3 of air at 2bar, 270C is compressed to 6bar pressure following PV1.3  = constant. It is expanded subsequently adiabatically to 2 bar. Considering two processes to be reversible, determine net work done, and also plot the processes on T - S diagrams.                                                                                                                                        

Sol:  V1 = 5m3, P1  = P3 = 2bar, P2  = 6bar, and n = 1.3

V2 = V1(P1/P2)1/1.3  = 5(2/6)1/1.3  = 2.147m3

Thus work done during process 1 - 2 is W1-2

= (P2V2  - P1V1)/(1- n)

= (6 × 105  × 2.47 - 2 x 105  × 5)/(1-1.3) = - 9.618 × 105  J

Likewise to obtain work done during processes 2 - 3, we apply

W2-3 = (P3V3  - P2V2)/(1 -   ); where      = 1.4

And V3 = V2(P2/P3)1/   = 2.147(6/2)1/1.4  = 4.705m3

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Posted Date: 10/15/2012 9:03:18 AM | Location : United States







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