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Determine net work done:
5m3 of air at 2bar, 270C is compressed to 6bar pressure following PV1.3 = constant. It is expanded subsequently adiabatically to 2 bar. Considering two processes to be reversible, determine net work done, and also plot the processes on T - S diagrams.
Sol: V1 = 5m3, P1 = P3 = 2bar, P2 = 6bar, and n = 1.3
V2 = V1(P1/P2)1/1.3 = 5(2/6)1/1.3 = 2.147m3
Thus work done during process 1 - 2 is W1-2
= (P2V2 - P1V1)/(1- n)
= (6 × 105 × 2.47 - 2 x 105 × 5)/(1-1.3) = - 9.618 × 105 J
Likewise to obtain work done during processes 2 - 3, we apply
W2-3 = (P3V3 - P2V2)/(1 - ); where = 1.4
And V3 = V2(P2/P3)1/ = 2.147(6/2)1/1.4 = 4.705m3
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how to resolve?
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