Determine elongation of bar:
A conical bar tapers uniformly from diameter of 4 cm to 1.5 cm in length of 40 cm. If axial force of 80 kN is applied at each end, determine elongation of bar. Take E = 2 × 105 N/mm^{2}
Sol.: Given; P = 80 × 103 N,
E = 200GPa = 2 × 10^{5} N/mm^{2}, dL = 40mm, d_{2} = 15mm, L = 400mm
As;
By putting all the value, we get
δL = [4 × 80 × 10^{3} × 400]/[Π(2 × 10^{5}) × (40 × 15)]
= 0.3397mm .......ANS