Already have an account? Get multiple benefits of using own account!
Login in your account..!
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
Determine change in length of the bar:
A steel bar is subjected to loads as shown the given figure. Determine change in length of the bar ABCD of 18 cm diameter. E = 180 kN/mm2.
As d = 180mm
E = 180 × 103 N/mm2
LAB = 300mm
LBC = 310mm
LCD = 310mm
From the given figure
Load on portion AB = PAB = 50 × 103 N
Load on portion BC = PBC = 20 × 103 N
Load on portion CD = PCD = 60 × 103 N
Area of portion AB = Area of portion BC = Area of portion CD = A = Πd2/4
= (180)2/4 = 25446.9 mm2
By using relation l = Pl/AE
δLab = (50 × 103 × 300)/( 25446.9 × 180 × 103) = 0.0033mm ---------------- Compression
δLbc = (20 × 103 × 310)/( 25446.9 × 180 × 103) = 0.0012mm ---------------- Compression δLcd = (60 × 103 × 310)/( 25446.9 × 180 × 103) = 0.0041mm ---------------- Compression As net change in length = - δ Lab - δ Lbc - δ Lcd
= - 0.0033 - 0.0012 - 0.0041
= - 0.00856 mm
Decrease in length = 0.00856mm .......ANS
A person climbs up a escalator in 60s . When he stands on it , then he is carried in the moving escalator in 30s . How much time will he take in climbing up in a moving escalator?
Q. Material Selection for Insulation? Material for 15ºC to 650ºC temp range is Calcium Silicate, Manville Thermo-12 or approved equivalent. Material for -18ºC to 230ºC temp.
(a) A spring mass system has a period 0.25 sec. What will be the new period if spring constant is increased by 50% ? (b) A vibratory system in a vehicle is to be prepared with t
whats is apossitive wrench??
Q. How can you determine velocity by electromagnetic method? In electromagnetic method, a magnetic field is generated by the electric current flowing through a coil fixed below
what is angle of friction
Find out the moment of inertia of an annular area: Find out the M. I. of an annular area among two circles where difference of radius is quite small, around any centroidal axi
Under Damping If the restoring force is larger than friction, and the oscillation is classified as under-damped. In this case, ω is real and behaves exactly like the solu
Grinder: Grinders are used to sharpen the cutting edges of the tools. They are basically fast rotating grinding wheels carried at one or two ends of a shaft. The grinding wheel ar
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd