Define elastic fatigue, Physics

It is the need of elastic strength of a substance when subjected to repeated stresses and strain. If the substance is reserved undisturbed for some time, the previous properties are restored. Therefore elastic fatigue is a temporary phenomenon.

 

Posted Date: 4/15/2013 1:12:31 AM | Location : United States







Related Discussions:- Define elastic fatigue, Assignment Help, Ask Question on Define elastic fatigue, Get Answer, Expert's Help, Define elastic fatigue Discussions

Write discussion on Define elastic fatigue
Your posts are moderated
Related Questions
Explain about the inverse piezoelectric effect. Inverse piezoelectric effect: While an alternating e.m.f is applied to the opposed faces of a quartz or tourmaline crystal th

On the basis of mutual interactions or behavior of several materials in an external magnetic field, the materials are dividing in three basic categories. (i) Diamagnetic materi

What are the electron microscopy application areas? Electron microscopy application areas are as follows: a. Biology and life sciences b. Semiconductor and data storage

Define in detail about the test and characteristics of good bricks. Tests for bricks 1. Absorption a brick is taken and it is weighed dry. It is then immersed in water for

When the curve is not simple or linear as diode valve is known as non-ohmic device.

Photons and gravity : It is observed that light is affected by gravity. We can recognize the gravitational behaviour of light from the fact that although a photon has zero rest mas

For a reversible process involving ideal gases in a closed system, show that ΔS = C v ln(T 2 /T 1 ) for a constant volume process ΔS = C p ln(T 2 /T 1 ) for a constant pres

some details about wave

Constant Negative Velocity Observe in which the object below moves along with a constant velocity within the negative direction. The dot diagram displays in which each consecut

The magnetic induction at a point 15 cm from a long straight wire carrying a current is 4 X 10 -6 T Compute the current. (J - 12) B = μ o I/2πa I = 2πa X B/μo Current I