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Using DEBUG
DEBUG.COM is a DOS efficacy that facilitates the trouble-shooting and debugging of assembly language programs. In particular case of personal computers, all of the resources, processor and memory resource management functions are carried out by the operating systems. Therefore, users have very little control on the computer hardware at lower levels. The DEBUG efficacy enables you to have the control of these resources up to some extent. In the easier, rather then, basic words, the DEBUG enable you to use the personal computer as a low level microprocessor kit.
The DEBUG command at DOS prompt invokes this facility. A '_' (dash) display signals the successful invoke operation of DEBUG, further that is used as DEBUG prompt for debugging commands. Following command line, DEBUG prompt and the DEBUG command character display describe the DEBUG command entry procedure, as in given Figure.
A valid command is accepted by using the enter key. The list of typically used valid commands of DEBUG is given in Table namely DUBEG command along with their respective syntax.
The program DEBUG can be used either to debug a source program or to view the results of execution of an .EXE file with the help of the .LST file and the above commands. The .LST file indicates the offset address allotments for result variables of a program in the specific segment. After the execution of the program is completed the offset address of the result variables can be observed by using the d command. The results available in the registers may be view by using the r command. So the DEBUG offers a reasonably good platform for trouble-shooting executing and observing the results of the assembly language programs. Here one should remember that the DEBUG is able to only trouble-shoot the .EXE files.
Assume that the registers are initialized to EAX=12345h,EBX =9528h ECX=1275h,EDX=3001h sub AH,AH sub DH,DH mov DL,AL mov CL,3 shl DX,CL shl AX,1 add DX,AX
what will be the value of EAX after following instructions execute? mov bx, 0FFFFh and bx, 6Bh
Memory Segmentation : The memory in an 8086/8088 based system is organized as segmented memory. In this scheme, the whole physically available memory can be divided into a n
Program is written but has errors returning values from the procedure.
1. Start your program at address $8500. To do this you need to inform the assembler, through the EQU and ORG assembler directives, that you want your program to start at $8500. Thi
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how to code
Write a MC68HC12 assembly language program to average ten 16-bit values that are stored starting at address $1100. Place the two-byte result at $1110. Use indexed addressing. Us
from pin description it seems that 8086 has 16 address/data lines i.e.AD0_AD15.The physical address is however is larger than 2^16.How this condition can be handled
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