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Can copy constructor admit an object of the same class as parameter, rather than reference of the object?
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Pointers are just numbers, representing addresses in memory. You can add to and subtract from pointers, for instance. It is pretty easy to make mistakes with pointer math, however,
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Write a program to find the area under the curve y = f(x) between x = a and x = b, integrate y = f(x) between the limits of a and b. The area under a curve betw
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A: No. this is specified in the definition of the copy constructor itself. It must generate an error if a programmer specifies a copy constructor along a first argument that is an object and not a reference.
constructor with a single argument creates that constructor as conversion ctor and it can be utilized for type conversion. For instance: class Boo { public: Boo ( int i ); }; Boo BooObject = 10; // assigning int 10 Boo object
constructor with a single argument creates that constructor as conversion ctor and it can be utilized for type conversion.
For instance:
class Boo
{
public:
Boo ( int i );
};
Boo BooObject = 10; // assigning int 10 Boo object
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