Calculation of caco3 equivalents, Chemistry

Q. Analysis of water gave the following results H2SO4 = 196Mg/L; MgSO4 = 24Mg/L, CaSO4 = 272Mg/L and NaCl = 25Mg/L. Water is to be supplied to the town of the population of one lake only. The daily consumption of water is 50 Litre per head. Calculate the cost of the cost of Lime soda required for the softening of hard water for town for the month of April 2002. If the cost of lime is Rs.5/-per Kg and soda is Rs.8/-per Kg.

Ans. Calculation of CaCO3 equivalents

constituent

amount

multiplication

CaCO3 equivalent

Requirement

H2SO4

196

100/98

196*100/98 = 200 Mg/L

L + S

MgSO4

24

100/120

24*100/120 = 20 Mg/L

 L + S

CaSO4

272

100/136

272*100/120 = 20Mg/L

 S

NaCl

25

  -

Does not create hardness

  -

Amount of Lime required: = 74/100[H2SO4 + MgSO4]*Vol. Of water

                                                 = 74/100[200 + 20]*50*100000

                                                 = 814*106 mg = 814 kg/day

Amount of soda required: = 106/100[H2SO4 + MgSO4 +CaSO4]*Vol. Of water

                                                 = 106/100[200 + 20 + 200]*50*100000

                                                 = 2226*106

                                                 = 2226Kg/day

Cost of lime and soda for the month of April 30 days

Cost of lime = 814*30*5 = Rs. 122100

Cost of soda = 2226*30*8 = Rs. 534240

Posted Date: 7/21/2012 9:20:30 AM | Location : United States







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