Q. Analysis of water gave the following results H₂SO₄ = 196Mg/L; MgSO₄ = 24Mg/L, CaSO₄ = 272Mg/L and NaCl = 25Mg/L. Water is to be supplied to the town of the population of one lake only. The daily consumption of water is 50 Litre per head. Calculate the cost of the cost of Lime soda required for the softening of hard water for town for the month of April 2002. If the cost of lime is Rs.5/-per Kg and soda is Rs.8/-per Kg.

Ans. Calculation of CaCO₃ equivalents

constituent	amount	multiplication	CaCO3 equivalent	Requirement
H2SO4	196	100/98	196*100/98 = 200 Mg/L	L + S
MgSO4	24	100/120	24*100/120 = 20 Mg/L	L + S
CaSO4	272	100/136	272*100/120 = 20Mg/L	S
NaCl	25	-	Does not create hardness	-

Amount of Lime required: = 74/100[H₂SO₄ + MgSO₄]*Vol. Of water

                                                 = 74/100[200 + 20]*50*100000

                                                 = 814*10⁶ mg = 814 kg/day

Amount of soda required: = 106/100[H₂SO₄ + MgSO₄ +CaSO₄]*Vol. Of water

                                                 = 106/100[200 + 20 + 200]*50*100000

                                                 = 2226*10⁶

                                                 = 2226Kg/day

Cost of lime and soda for the month of April 30 days

Cost of lime = 814*30*5 = Rs. 122100

Cost of soda = 2226*30*8 = Rs. 534240

Posted Date: 7/21/2012 9:20:30 AM | Location : United States

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