Calculate the machining time and the material removal rate, Mechanical Engineering

Calculate the Machining Time and the Material Removal Rate

A through hole of 40 mm diameter and 50 mm depth is to be drilled in a mild steel component. The cutting speed can be taken as 65 m/min and the feed rate as 0.25 mm/rev. calculate the machining time and the material removal rate.

Solution

Given  V = 65 m/min

f = 0.25 mm/rev

D = 40 mm

L = 50 mm

 Spindle speed

 N = (1000 × 65)/ (π× 40)

 = 527.35 rev/min

= 520 rev/min

Breakthrough distance

A =40 /2 tan 59o

Total length of drill travel L = 50 + 12 + 3 = 65 mm

Time for drilling the hole = 65/ (0.25 × 520) = 0.50 minutes

The material removal rate = (π× 402 × 0.25 × 520) /4

= 163362.82 mm3/min

= 163.363 cm3/min.

Posted Date: 12/26/2012 8:15:54 AM | Location : United States







Related Discussions:- Calculate the machining time and the material removal rate, Assignment Help, Ask Question on Calculate the machining time and the material removal rate, Get Answer, Expert's Help, Calculate the machining time and the material removal rate Discussions

Write discussion on Calculate the machining time and the material removal rate
Your posts are moderated
Related Questions
Arc strikes Represent any localised heat affected zone caused by an arc. Arc strike tends to produce hardening particularly in high carbon steels and alloy steels. Grinding of

Determine tension in horizontal rope: Q:  A 500N cylinder, 1 m in diameter is loaded between cross pieces AE and BD that make an angle of 60º with each other and are pinn

(a) Write short note on following : (i) Ericsson cycle (ii) Diesel cycle (iii) Stirling cycle (b) The swept volume of a diesel cycle engine working on dual cycle is 0.0

What is entropy microscopically

MIG / CO 2 WELDING In MIG / CO 2 welding the feeding of filler wire is machanised. If the welder moves the MIG / CO 2 torch the process is called semi automatic MIG / CO 2

Titanium Alloys Pure titanium is a light weight and strong ductile metal. This is very strong and as well as highly resistant to corrosion of all kinds but has the drawback su

point load in overhanging beams

The ARM microprocessor has 32 bit instructions and 32 bit registers. Explain why this means that immediate addressing cannot be used to load a register with a 32 bit constant. T

Spray Transfer In a gas shield of argon or argon rich mixture [i.e., Ar+CO 2 gas mixture containing more than 80 % argon] the metal transfer changes from globular to spray typ