C program for count the no which you want , C/C++ Programming

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# include stdio.h>

# include string.h>

# include conio.h>

void main()

{

          int i=0,j=0,b=0,count=0;

          int a[100];

          for(i=0;i<100;i++)

          {

                   a[i]=0;

          }

          i=0;

          clrscr();

          printf("\nENTER THE LIMIT OF NO: ");

          flushall();

          scanf("%d",&j);

          for(i=0;i

          {

                   printf("\nENTER THE NO %d:-",i+1);

                   scanf("%d",&a[i]);

          }

 

          printf("\nENTER THE NO THAT U WANT TO COUNT: ");

          flushall();

          scanf("%d",&b);

          for(i=0;i

          {

                   if(b==a[i])

                   {

                             count++;

                   }

          }

          printf("\nTHE NO %d IS REPEATED %d TIMES",b,count);

          getch();

}

 

OUTPUT :

ENTER THE LIMIT OF NO: 4

ENTER THE NO 1 : 5

ENTER THE NO 2 : 4

ENTER THE NO 3 : 4

ENTER THE NO 4 : 4

THE NO 4 IS REPEATED 3 TIMES


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