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Q. A small pin fixed on a table top is viewed from above from a distance of 50 cm. By what distance would the pin appear to be raised if it is viewed from the same point through a 15 cm thick glass slab held parallel to the table? Refractive index of glass = 1.5. Does the answer depend on the location of the slab?
Answer
Actual depth of the pin d = 15cm
The Apparent dept of the pin = d'
A Refractive index of glass μ = 1.5
Ratio of real depth to the apparent depth is equal to the refractive index of glass
i. e.
The distance at which the pin show to be raised=d'-d
15 - 10 = 5 cm
For a small angle of incidence this distance doesn't depend up on the location of the slab.
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