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In this sorting algorithm, multiple swapping occurs in one pass. Smaller elements move or 'bubble' up to the top of the list, so the name given to the algorithm.
In this method, adjacent members of list to be sorted are compared. If item over the top is greater than the item instantly below it, then they are swapped. This procedure is carried on until the list is sorted.
The detailed algorithm is like as:
Algorithm: BUBBLE SORT
1. Begin
2. Read the n elements
3. for i=1 to n
for j=n downto i+1
if a[j] <= a[j-1]
swap(a[j],a[j-1])
4. End // of Bubble Sort
Total number of comparisons in Bubble sort will be:
= (N-1) +(N-2) . . . + 2 + 1
= (N-1)*N / 2 =O(N2)
This inefficiency is because of the fact that an item moves only to the next position in each pass.
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Q. Assume that we have separated n elements in to m sorted lists. Explain how to generate a single sorted list of all n elements in time O (n log m )?
one to many one to one many to many many to one
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I want to study example
I need help writing a pseudocode for my assignment can anyone help?
Encryption the plain-text using the round keys: 1. (Key schedule) Implement an algorithm that will take a 128 bit key and generate the round keys for the AES encryption/decryp
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