Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
Write a program to find the area under the curve y = f(x) between x = a and x = b, integrate y = f(x) between the limits of a and b. The area under a curve between two points can be found by doing a definite integral between the two points.
Solution:
#include float start_point, /* GLOBAL VARIABLES */ end_point, total_area; int numtraps; main( ) { void input(void); float find_area(float a,float b,int n); /* prototype */ print(“AREA UNDER A CURVE”); input( ); total_area = find_area(start_point, end_point, numtraps); printf(“TOTAL AREA = %f”, total_area); } void input(void) { printf(“\n Enter lower limit:”); scanf(“%f”, &start_point); printf(“Enter upper limit:”); scanf(“%f”, &end_point); printf(“Enter number of trapezoids:”); scanf(“%d”, &numtraps); } float find_area(float a, float b, int n) { floatbase, lower, h1, h2; /* LOCAL VARIABLES */ float function_x(float x); /* prototype */ float trap_area(float h1,float h2,floatbase);/*prototype*/ base = (b-1)/n; lower = a; for(lower =a; lower <= b-base; lower = lower + base) { h1 = function_x(lower); h1 = function_x(lower + base); total_area += trap_area(h1, h2, base); } return(total_area); float trap_area(float height_1,float height_2,floatbase) { float area; /* LOCAL VARIABLE */ area = 0.5 * (height_1 + height_2) * base; return(area); } float function_x(float x) { /* F(X) = X * X + 1 */ return(x*x + 1); } Output AREA UNDER A CURVE Enter lower limit: 0 Enter upper limit: 3 Enter number of trapezoids: 30 TOTAL AREA = 12.005000 AREA UNDER A CURVE Enter lower limit: 0 Enter upper limit: 3 Enter number of trapezoids: 100 TOTAL AREA = 12.000438
EVOLUTION OF A COMPUTER: Although 'computer', as we understand it today, is relatively of recent innovation, its development rests on centuries' of research. This section pres
The instructions of the logic functions are: and not, or and xor. These act on the bits of their operators. To make sure the result of the operations we revolve to the cmp and test
Hardware Hardware includes the cable and a Hub/Switch that will connect the participating computers together. Printers or any other peripherals connected to one computer can
Process of Data mining Data mining is an iterative process that typically involves the following phases: Problem definition A data mining project starts with the understanding o
Which applications require TCP and why? Also specify which applications require UDP and why? A4) TCP is also known as connection-oriented: setup required between client and server
Computerised Systems : You would have realized by now that computing systems are most useful for manipulating information. Any organisation and management of information basically
Printer output : Consider what is required here. Do you just require management information on the one hand or camera copy for reprographic purposes? Inkjet Very quiet. C
Memory unit of computer: The Memory unit is an important component of a computer where all the data and information are stored in the form of binary digits (combination of 0
Question 1 What is IT auditing? Discuss the three phases involved in the IT auditing Question 2 List and explain the two types of load balancing methods Question 3
What is a computer??
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd