Algorithm to sort a given list by quick sort method, Data Structure & Algorithms

Assignment Help:

Q. Write down an algorithm to sort a given list by making use of Quick sort method. Describe the behaviour of Quick sort when input given to us is already sorted.                                  

Ans.

Algorithm for Quick Sort is written below

QUICK(A, N, BEG, END, LOC)

Here A is an array with N element. Parameter BEG

and END comprises the   boundary value of the sub

list of A to which this method applies. LOC keeps track of the position of the first element A[BEG] of the sublist during the particular procedure. The local varrible LEFT     and  RIGHT will contain the boundary value of the list elements that have not been scanned.

1. [Initialize]   Set LEFT:=BEG, RIGHT;=END and LOC:=BEG.

2. [Scan from left to right]

(a) Repeat while A[LOC] <=A[RIGHT] and LOC!=RIGHT; RIGHT:=RIGHT-1; [End of loop]

(b)If LOC= RIGHT, then Return;

(c)If A[LOC ] > A[RIGHT],then: [Interchange    A[LOC] and A[RIGHT]] TEMP:=  A[LOC]  ,A[LOC] =  A[RIGHT] , A[RIGHT] :=TEMP;

(i) Set LOC =RIGHT

(ii)      Go to step 3

3.[Scan from left to right]

repeat while A[LEFT] <=A[LOC] and  LEFT!= LOC; LEFT := LEFT +1; [End of loop]

(a) If LOC  =LEFT, then Return;

(b) If  A[LEFT]  > A[LOC] ,then

(i) [Interchange A[LEFT]  and A[LOC]] TEMP:=A[LOC],A[LOC]:=A[LEFT] . A[LEFT]:= TEMP

(ii) Set LOC :=LEFT (iii) Go to Step 2; [End of if structure]

(Quicksort) This algorithm sorts an array A with N elements.

1. [Intialize.] TOP := NULL

2. [Push boundary values of A onto stacks when A has 2 or more elements.]

If  N>1, then: TOP+1,LOWER [1]:=1, UPPER [1]: =N

3. Repeat steps 4 to 7 while TOP != NULL.

4. [Pop sublist from stacks.]

Set BEG: =LOWER[TOP], END:=UPPER[TOP], TOP:=TOP-1.

5. Call QUICK (A, N, BEG, END, LOC). [ Push left

sublist onto stacks when it has 2 or more elements.]

If BEG < LOC -1, then:

TOP:= TOP+1, LOWER[TOP] := BEG, UPPER[TOP]= LOC -1.

[End of If structure.]

6. [Push right sublist onto stacks when it has 2

or more elements.]

If  LOC +1< END , then:

TOP := TOP+1, LOWER[TOP] := LOC +1, UPPER[TOP] := END.

[End of If structure .] [End of Step 3 loop.]

7. Exit.

The behaviour of quick sort when the list is sorted is of order O(n2) as this is the worst case for quicksort


Related Discussions:- Algorithm to sort a given list by quick sort method

What is complexity, Complexity is the rate at which the needed storage or c...

Complexity is the rate at which the needed storage or consumed time rise as a function of the problem size. The absolute growth based on the machine utilized to execute the program

Use a random number generator to create 10 numbers, Use a random number gen...

Use a random number generator to create 10 numbers between 1 and 1000 and store them in 2 different arrays.  The first array should contain the numbers as they are generated.  The

Design a time algorithm, Q. An, array, A comprises of n unique integers fro...

Q. An, array, A comprises of n unique integers from the range x to y(x and y inclusive where n=y-x). Which means, there is only one member that is not in A. Design an O(n) time alg

Explain in detail about the ruby arrays, Explain in detail about the Ruby a...

Explain in detail about the Ruby arrays Ruby arrays have many interesting and powerful methods. Besides indexing operations which go well beyond those discussed above, arrays h

Procedure of analysis of algorithm, Example 1:  Following are Simple sequen...

Example 1:  Following are Simple sequence of statements Statement 1;  Statement 2; ... ... Statement k; The entire time can be found out through adding the times for

Efficient way of storing a sparse matrix in memory, Explain an efficient wa...

Explain an efficient way of storing a sparse matrix in memory.   A matrix in which number of zero entries are much higher than the number of non zero entries is called sparse mat

Explain about greedy technique, Explain about greedy technique The  gre...

Explain about greedy technique The  greedy  method  suggests  constructing  a   solution  to  an  optimization  problem   by  a sequence of steps, every expanding a partially c

Explain the concept of colouring, Colouring The use of colours in CAD/C...

Colouring The use of colours in CAD/CAM has two main objectives : facilitate creating geometry and display images. Colours can be used in geometric construction. In this case,

Depth-first search (dfs) , In this respect depth-first search (DFS) is the...

In this respect depth-first search (DFS) is the exact reverse process: whenever it sends a new node, it immediately continues to extend from it. It sends back to previously explore

Hw7, Handout 15 COMP 264: Introduction to Computer Systems (Section 001) Sp...

Handout 15 COMP 264: Introduction to Computer Systems (Section 001) Spring 2013 R. I. Greenberg Computer Science Department Loyola University Water TowerCampus, Lewis Towers 524 82

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd