How to calculate [oh-] in the aqueous solution

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Calculate [OH-] in the following aqueous solution at 25 deg C: [H3O+] = 3.6×10^?2 M? I know you have to divide 1x10^-14 by the 3.6x10^-2 and the answer I got was 2.8x10^-17 but it said my answer is wrong

Reference no: EM13298411

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How to calculate [oh-] in the aqueous solution : Calculate [OH-] in the following aqueous solution at 25 deg C: [H3O+] = 3.6×10^?2 M? I know you have to divide 1x10^-14 by the 3.6x10^-2 and the answer I got was 2.8x10^-17 but it said my answer is wrong
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