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# Intensity Due To Field Charges Assignment Help

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Electrostatics - Intensity Due To Field Charges

**Intensity Due To Field Charges**

The electric field intensity at any point due to a group of point charges is equal to the vector sum of the electric field intensities due to individual charges at the same point. For this, we first calculate the electric field intensity at the given point due to individual charges, as if other charges were not there and then add them vectorially i.e.

** **

** ** (1)

Here, **r**_{1} is the distance of the point **P** from the ith charge **Q**_{1} and ~r_{1} is unit vector directed from **Q**_{1} to the point **P**.

Now suppose the point charges **Q**_{1}, Q_{2}, Q_{3}, …. Q_{n} are located in vacuum at positions

respectively. We have to calculate electric field intensity (~E) at any point P where position is ~r. As a net force **P** is vector sum of the forces due to individual charges, therefore, we can write

**As **

** (2)**

Note that ~E is a vector quantity that varies from one point to another point in space and its value depends on the positions of the source charges, using polygon law of vectors.

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**Intensity Due To Field Charges**

**(1)**

Here,

**r**is the distance of the point

_{1}**P**from the ith charge

**Q**

_{1}and ~r

_{1}is unit vector directed from

**Q**

_{1}to the point

**P**.

Now suppose the point charges

**Q**

_{1}, Q_{2}, Q_{3}, …. Q_{n}are located in vacuum at positions

respectively. We have to calculate electric field intensity (~E) at any point P where position is ~r. As a net force

**P**is vector sum of the forces due to individual charges, therefore, we can write

**As**

**(2)**

Note that ~E is a vector quantity that varies from one point to another point in space and its value depends on the positions of the source charges, using polygon law of vectors.